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In the hydrocarbon CH3—CH=CH—CH2—C≡CH, the state of hybridization of carbons 1, 3 and 5 are in the following sequence:
- sp2, sp3, sp3
- sp, sp3, sp2
- sp2, sp2, sp3
- sp3, sp2, sp
Correct answer: sp2, sp3, sp3
Solution
The state of hybridization of the carbons in the given hydrocarbon is sp2 for the double-bonded carbon, sp3 for the single-bonded carbons.
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