Exams › JEE Main › Chemistry

Volume occupied by one molecule of water (density = 1 g cm^-3) is:

1. 9.0 × 10^-23 cm^3
2. 6.023 × 10^-23 cm^3
3. 3.0 × 10^-23 cm^3
4. 5.5 × 10^-23 cm^3

Correct answer: 3.0 × 10^-23 cm^3

Solution

The volume of one molecule of water can be calculated using the formula V = (4/3)πr^3, where r is the radius of the water molecule. The radius of a water molecule is approximately 1.4 Å, which is 1.4 × 10^-8 cm. Therefore, the volume of one molecule of water is approximately 3.0 × 10^-23 cm^3.

Related JEE Main Chemistry questions

• What volume of oxygen gas (O2) measured at 0°C and 1 atm, is needed to burn completely 11.2 L of propane gas (C3H8) measured under the same conditions?
• Number of moles of MnO4^- required to oxidize one mole of ferrous oxalate completely in acidic medium will be:
• The number of moles of KMnO4 that will be needed to react with one mole of sulphite ion in acidic solution is:
• An element, X has the following isotopic composition: 200X: 90%; 199X: 8.0%; 202X: 2.0%. The weighted average atomic mass of the naturally occurring element X is closest to:
• A 100 mL sample of a urea solution contains $6.02 \times 10^{20}$ molecules of urea. What is the molarity of the solution? (Take Avogadro constant, $N_A = 6.02 \times 10^{23}\ \text{mol}^{-1}$.)
• If the relative atomic mass unit were defined as $\frac{1}{6}$ of the mass of a carbon atom instead of $\frac{1}{12}$, then the mass of one mole of a substance would

⚔️ Practice JEE Main Chemistry free + battle 1v1 →