Given Fe3+(aq) + e− → Fe2+(aq); E° = +0.77 V Al3+(aq) + 3e− → Al(s); E° = −1.66 V Br2(aq) + 2e− → 2Br−; E° = +1.09 V Considering the electrode potentials, which of the following represents the correct order of reducing power?

Question

Accepted Answer

Al < Br− < Fe2+. The reducing power of a species is inversely related to its standard electrode potential; lower E° values indicate stronger reducing agents. Since Al has the lowest E° (-1.66 V), it is the strongest reducing agent, followed by Br− (E° = +1.09 V), and Fe2+ (E° = +0.77 V) is the weakest among the three.

Given Fe3+(aq) + e− → Fe2+(aq); E° = +0.77 V Al3+(aq) + 3e− → Al(s); E° = −1.66 V Br2(aq) + 2e− → 2Br−; E° = +1.09 V Considering the electrode potentials, which of the following represents the correct order of reducing power?

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