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In the reaction, CH3COOH LiAlH4 A PCl5 B Alc. KOH C, the product C is:

1. Acetaldehyde
2. Acetylene
3. Ethylene
4. Acetyl chloride

Correct answer: Ethylene

Solution

The reaction sequence involves the reduction of acetic acid (CH3COOH) with lithium aluminum hydride (LiAlH4) to form ethanol, which can then be dehydrated to produce ethylene (C2H4) when treated with potassium hydroxide (KOH). This transformation highlights the conversion of alcohol to an alkene through elimination.

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