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ExamsJEE MainChemistry

Given Reaction Energy Change (in kJ) Li(s) → Li(g) 161 Li(g) → Li⁺(g) 520 1/2 F₂(g) → F(g) 77 F(g) + e⁻ → F⁻(g) (Electron gain enthalpy) Li⁺(g) + F⁻(g) → LiF(s) -1047 Li(s) + 1/2 F₂(g) → LiF(s) -617 Based on data provided, the value of electron gain enthalpy of fluorine would be:

  1. -300 kJ mol⁻¹
  2. -350 kJ mol⁻¹
  3. -328 kJ mol⁻¹
  4. -228 kJ mol⁻¹

Correct answer: -328 kJ mol⁻¹

Solution

The electron gain enthalpy of fluorine can be calculated by rearranging the given thermochemical equations to find the energy change associated with the formation of F⁻ from F(g). The correct value of -328 kJ mol⁻¹ is derived from the overall energy balance of the reactions involving lithium and fluorine.

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