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Q47. Electrode potentials (E°) are given below: Cu2+/Cu = +0.52 V, Fe3+/Fe2+ = +0.77 V, 1/2 I2(s)/I− = +0.54 V, Ag+/Ag = +0.88 V. Based on the above potentials, strongest oxidizing agent will be :

1. Cu2+
2. Fe3+
3. I2
4. Ag+

Correct answer: Fe3+

Solution

Fe3+ has the highest standard electrode potential (+0.77 V) among the given options, indicating it has the greatest tendency to gain electrons and act as an oxidizing agent.

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