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CH3CH2COOH Cl2 / A → B alc. KOH → B. What is B ?

1. CH3CH2COCl
2. CH3CH2CHO
3. CH2=CHCOOH
4. ClCH2CH2COOH

Correct answer: CH2=CHCOOH

Solution

The reaction involves the conversion of propanoic acid (CH3CH2COOH) to an alkene (CH2=CHCOOH) through dehydrohalogenation after chlorination, which eliminates a hydrogen halide and forms a double bond.

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