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0.1 M solution of KI reacts with excess of H2SO4 and KIO3 solution. According to equation 5I- + IO3- + 6H+ → 3I2 + 3H2O Identify the correct statements : (A) 200 mL of KI solution reacts with 0.004 mol of KIO3. (B) 200 mL of KI solution reacts with 0.006 mol of H2SO4 (C) 0.5 L of KI solution produced 0.005 mol of I2 (D) Equivalent weight of KIO3 is equal to (Molecular weight / 5) Choose the correct answer from the options given below :

1. (A) and (D) only
2. (B) and (C) only
3. (A) and (B) only
4. (C) and (D) only

Correct answer: (A) and (D) only

Solution

Option (A) is correct because 0.1 M KI in 200 mL contains 0.02 moles of I-, which reacts with 0.004 moles of KIO3 according to the stoichiometry of the reaction. Option (D) is also correct as the equivalent weight of KIO3 is calculated by dividing its molecular weight by 5, based on the number of moles of I2 produced in the reaction.

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