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In the following substitution reaction : A benzene ring bearing Br at the top, Br at the upper-right position, and NO2 at the bottom is treated with C2H5ONa / C2H5OH → P product. Product 'P' formed is :

1. A benzene ring bearing OC2H5 at the top, Br at the upper-right position, and NO2 at the bottom.
2. A benzene ring bearing OC2H5 at the top, OC2H5 at the upper-right position, and NO2 at the bottom.
3. A benzene ring bearing Br at the top, OC2H5 at the upper-right position, and NO2 at the bottom.
4. A benzene ring bearing Br at the top, Br at the upper-right position, and OC2H5 at the bottom.

Correct answer: A benzene ring bearing OC2H5 at the top, Br at the upper-right position, and NO2 at the bottom.

Solution

The correct option is right because the reaction involves the substitution of the bromine atom at the top position of the benzene ring with an ethoxy group (OC2H5), while the other substituents, bromine and nitro, remain unchanged. This is consistent with the reactivity of the ethoxide ion, which acts as a nucleophile and replaces the bromine in a nucleophilic aromatic substitution.

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