Exams › JEE Main › Chemistry

When 81.0 g of aluminium is allowed to react with 128.0 g of oxygen gas, the mass of aluminium oxide produced in grams is _____. (Nearest integer) Given: Molar mass of Al is 27.0 g mol−1 Molar mass of O is 16.0 g mol−1

1. 153
2. 102
3. 204
4. 51

Correct answer: 153

Solution

The reaction between aluminium and oxygen produces aluminium oxide, and the limiting reactant determines the amount of product formed. In this case, 81.0 g of aluminium reacts with 128.0 g of oxygen, leading to the formation of 153 g of aluminium oxide based on stoichiometric calculations.

Related JEE Main Chemistry questions

• A 100 mL sample of a urea solution contains $6.02 \times 10^{20}$ molecules of urea. What is the molarity of the solution? (Take Avogadro constant, $N_A = 6.02 \times 10^{23}\ \text{mol}^{-1}$.)
• If the relative atomic mass unit were defined as $\frac{1}{6}$ of the mass of a carbon atom instead of $\frac{1}{12}$, then the mass of one mole of a substance would
• When 4.9 g of $\mathrm{H_2SO_4}$ reacts with NaCl, the products formed are 6 g of sodium hydrogen sulphate and 1.825 g of HCl. What mass of NaCl was decomposed?
• Which of the following has the least mass?
• What amount of magnesium phosphate, $\mathrm{Mg_3(PO_4)_2}$, in moles is needed to provide 0.25 mole of oxygen atoms?
• Haemoglobin has 0.33% iron by mass. If its molecular mass is about 67200 and the atomic mass of iron is 56, how many iron atoms are present in a single haemoglobin molecule?

⚔️ Practice JEE Main Chemistry free + battle 1v1 →