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FeO4^2− → Fe^3+ → Fe^2+ → Fe^0 The above diagram, the standard electrode potentials are given in volts (over the arrow). The value of E°(FeO4^2−/Fe^2+) is

1. 1.7 V
2. 1.2 V
3. 2.1 V
4. 1.4 V

Correct answer: 1.7 V

Solution

The standard electrode potential E°(FeO4^2−/Fe^2+) is determined by the difference in potential between the oxidation state of Fe in FeO4^2− and the reduction to Fe^2+, which is given as 1.7 V in the diagram.

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