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CaCO3(s) + 2HCl(aq) → CaCl2(aq) + CO2(g) + H2O(l) Consider the above reaction, what mass of CaCl2 will be formed if 250 mL of 0.76 M HCl reacts with 1000 g of CaCO3? (Given: Molar mass of Ca, C, O, H and Cl are 40, 12, 16, 1 and 35.5 g mol−1, respectively)

1. (1) 3.908 g
2. (2) 2.636 g
3. (3) 10.545 g
4. (4) 5.272 g

Correct answer: (3) 10.545 g

Solution

The correct option is based on stoichiometry; the reaction shows that one mole of CaCO3 produces one mole of CaCl2. By calculating the moles of HCl available and determining the limiting reactant, we find that the maximum mass of CaCl2 produced from the given amounts is 10.545 g.

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