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In Carius method for estimation of halogens, 180 mg of an organic compound produced 143.5 mg of AgCl. The percentage composition of chlorine in the compound is ____ %. [Given : Molar mass in g mol^-1 of Ag : 108, Cl = 35.5]

1. 20
2. 19
3. 21
4. 18

Correct answer: 20

Solution

To find the percentage of chlorine in the compound, we first calculate the moles of AgCl produced using its molar mass (143.5 mg AgCl / 143.5 g/mol = 0.001 mol). Since each mole of AgCl contains one mole of Cl, we have 0.001 mol of Cl, which corresponds to 0.001 mol x 35.5 g/mol = 0.0355 g of Cl. The percentage of chlorine in the compound is then (0.0355 g / 0.180 g) x 100% = 19.72%, which rounds to approximately 20%.

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