If equal number of H₂, I₂ and HI molecules are present at equilibrium for the reaction H₂(g) + I₂(g) ⇌ 2HI(g), the Kp for the process is x × 10⁻¹, x = ______ [Given : R = 0.082 L atm K⁻¹ mol⁻¹]

Question

Accepted Answer

(3) 10. At equilibrium, the partial pressures of H₂ and I₂ are equal and can be represented as 'p', while the partial pressure of HI is '2p' due to the stoichiometry of the reaction. The equilibrium constant Kp is calculated using the formula Kp = (P_HI^2) / (P_H2 * P_I2), which simplifies to Kp = (2p)^2 / (p * p) = 4, leading to Kp = 10 when expressed in the form x × 10⁻¹.

If equal number of H₂, I₂ and HI molecules are present at equilibrium for the reaction H₂(g) + I₂(g) ⇌ 2HI(g), the Kp for the process is x × 10⁻¹, x = ______ [Given : R = 0.082 L atm K⁻¹ mol⁻¹]

Solution

Related JEE Main Chemistry questions