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ExamsJEE MainChemistry

Match List-I with List-II. List-I (Reaction) (A) Phenol → salicylic acid derivative (o-hydroxybenzoic acid) (B) Phenol → o-hydroxybenzaldehyde (C) Phenol → p-benzoquinone (D) Phenol → anisole List-II (Reagent(s)) (I) Na2Cr2O7, H2SO4 (II) (i) NaOH (ii) CHCl3 (III) (i) NaOH, CHCl3 (ii) NaOH (iii) HCl (IV) (i) NaOH (ii) CO2 (iii) HCl Choose the correct answer from the options given below:

  1. (1) (A)-(IV); (B)-(I); (C)-(III); (D)-(II)
  2. (2) (A)-(IV); (B)-(III); (C)-(I); (D)-(II)
  3. (3) (A)-(II); (B)-(III); (C)-(I); (D)-(IV)
  4. (4) (A)-(II); (B)-(I); (C)-(III); (D)-(IV)

Correct answer: (1) (A)-(IV); (B)-(I); (C)-(III); (D)-(II)

Solution

The correct option matches each reaction with the appropriate reagents: salicylic acid is formed from phenol using sodium hydroxide, carbon dioxide, and hydrochloric acid; o-hydroxybenzaldehyde is produced via oxidation with sodium dichromate and sulfuric acid; p-benzoquinone is generated through a specific oxidation process; and anisole is synthesized using sodium hydroxide and chloroform.

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