Exams › JEE Main › Chemistry

The ascending order of acidity of –OH group in the following compounds is : (A) Bu–OH (B) O2N–C6H4–OH (C) MeO–C6H4–OH (D) C6H5–OH (E) O2N–C6H3(NO2)–OH Choose the correct answer from the options given below :

1. (C) < (A) < (D) < (B) < (E)
2. (A) < (C) < (D) < (B) < (E)
3. (A) < (D) < (C) < (B) < (E)
4. (C) < (D) < (B) < (A) < (E)

Correct answer: (A) < (C) < (D) < (B) < (E)

Solution

The acidity of the –OH group in these compounds is influenced by the presence of electron-withdrawing or electron-donating groups. In this case, the order reflects that alkyl groups (like in Bu–OH) are less acidic than phenolic compounds, while nitro groups (as in O2N–C6H4–OH and O2N–C6H3(NO2)–OH) significantly increase acidity due to their strong electron-withdrawing effect.

Related JEE Main Chemistry questions

• Why is ortho-nitrophenol less soluble in water than the meta- and para-nitrophenol isomers?
• Which of the following structures represents vinylcarbinol?
• Which separation technique is most appropriate for a 1:1 mixture of ortho-nitrophenol and para-nitrophenol?
• Which of the following is NOT a starting material used for the preparation of iodoform?
• Iodoform is formed from all of the following except:
• Which reagent can convert CH$_3$CH$_2$OH into CH$_3$CHO?

⚔️ Practice JEE Main Chemistry free + battle 1v1 →