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For the reaction RCH2Br + I− —acetone→ RCH2I + Br− The correct statement is

1. Br− can act as competing nucleophile.
2. The reaction can occur in acetic acid also.
3. The transition state formed in the above reaction is less polar than the localised anion.
4. The solvent used in the reaction solvates the ions formed in rate determining step.

Correct answer: The transition state formed in the above reaction is less polar than the localised anion.

Solution

The transition state in this reaction is less polar than the localized anion because it represents a state where the bond formation and bond breaking are in progress, leading to a more balanced charge distribution compared to the fully formed anion.

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