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Choose the correct option for the following reactions. B —(BH3, H2O2/OH−)→ [product] [alkene] —(Hg(OAc)2, H2O; NaBH4)→ A

1. ‘A’ and ‘B’ are both Markovnikov addition products
2. ‘A’ is Markovnikov product and ‘B’ is anti-Markovnikov product
3. ‘A’ and ‘B’ are both anti-Markovnikov products
4. ‘B’ is Markovnikov and ‘A’ is anti-Markovnikov product

Correct answer: ‘A’ and ‘B’ are both anti-Markovnikov products

Solution

Both reactions involve the addition of water across double bonds, where the regioselectivity leads to the formation of anti-Markovnikov products. In the first reaction, the hydroboration-oxidation mechanism results in the addition of water to the less substituted carbon, while the second reaction also follows a similar pattern, confirming that both products are indeed anti-Markovnikov.

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