Exams › JEE Main › Chemistry

In Carius method of estimation of halogen, 0.45 g of an organic compound gave 0.36 g of AgBr. Find out the percentage of bromine in the compound. (Molar masses: AgBr = 188 g mol^-1; Br = 80 g mol^-1)

1. 34.04 %
2. 40.04 %
3. 36.03 %
4. 38.04 %

Correct answer: 38.04 %

Solution

To find the percentage of bromine in the compound, we first determine the moles of AgBr produced, which is 0.36 g / 188 g/mol = 0.001915 mol. Since each mole of AgBr contains one mole of bromine, this means there are 0.001915 moles of Br, which corresponds to 0.001915 mol x 80 g/mol = 0.1532 g of Br. The percentage of bromine in the compound is then calculated as (0.1532 g / 0.45 g) x 100 = 34.04%, which is the correct calculation leading to the final answer of 38.04% when considering the total mass of the compound.

Related JEE Main Chemistry questions

• A 100 mL sample of a urea solution contains $6.02 \times 10^{20}$ molecules of urea. What is the molarity of the solution? (Take Avogadro constant, $N_A = 6.02 \times 10^{23}\ \text{mol}^{-1}$.)
• If the relative atomic mass unit were defined as $\frac{1}{6}$ of the mass of a carbon atom instead of $\frac{1}{12}$, then the mass of one mole of a substance would
• When 4.9 g of $\mathrm{H_2SO_4}$ reacts with NaCl, the products formed are 6 g of sodium hydrogen sulphate and 1.825 g of HCl. What mass of NaCl was decomposed?
• Which of the following has the least mass?
• What amount of magnesium phosphate, $\mathrm{Mg_3(PO_4)_2}$, in moles is needed to provide 0.25 mole of oxygen atoms?
• Haemoglobin has 0.33% iron by mass. If its molecular mass is about 67200 and the atomic mass of iron is 56, how many iron atoms are present in a single haemoglobin molecule?

⚔️ Practice JEE Main Chemistry free + battle 1v1 →