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ExamsJEE MainChemistry

2O3(g) ⇌ 3O2(g) At 300 K, ozone is fifty percent dissociated. The standard free energy change at this temperature and 1 atm pressure is ________ J mol−1. (Nearest integer) [Given: ln 1.35 = 0.3 and R = 8.3 J K−1 mol−1]

  1. 747.00
  2. 747.00
  3. 747.00
  4. 747.00

Correct answer: 747.00

Solution

The standard free energy change can be calculated using the relationship between the equilibrium constant and free energy. Given that ozone is fifty percent dissociated, the equilibrium constant can be determined, and applying the formula ΔG° = -RT ln K leads to the calculated value of 747.00 J mol−1.

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