StreakPeaked· Practice

ExamsJEE MainChemistry

Match List-I with List-II. List-I (a) Sodium Carbonate (b) Titanium (c) Chlorine (d) Sodium hydroxide List-II (i) Deacon (ii) Castner-Kellner (iii) Van-Arkel (iv) Solvay Choose the correct answer from the options given below :

  1. (a) → (iv), (b) → (iii), (c) → (i), (d) → (ii)
  2. (a) → (i), (b) → (iii), (c) → (iv), (d) → (ii)
  3. (a) → (iv), (b) → (i), (c) → (ii), (d) → (iii)
  4. (a) → (iii), (b) → (i), (c) → (ii), (d) → (iv)

Correct answer: (a) → (iv), (b) → (iii), (c) → (i), (d) → (ii)

Solution

The correct matches are based on the industrial processes associated with each compound or element: Sodium Carbonate is produced via the Solvay process, Titanium is extracted using the Van-Arkel method, Chlorine is produced through the Deacon process, and Sodium hydroxide is obtained through the Castner-Kellner process.

Related JEE Main Chemistry questions

⚔️ Practice JEE Main Chemistry free + battle 1v1 →