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The solubility of AgCN in a buffer solution of pH = 3 is x. The value of x is: [Assume : No cyanocomplex is formed; Ksp(AgCN) = 2.2 × 10−16 and Ka(HCN) = 6.2 × 10−10]
- 0.625 × 10−6
- 1.9 × 10−5
- 2.2 × 10−16
- 4.6 × 10−8
Correct answer: 1.9 × 10−5
Solution
The correct option is right because at pH 3, the concentration of H+ ions is high, which shifts the equilibrium of the dissociation of HCN to the left, reducing the concentration of CN- ions in solution. This allows more AgCN to dissolve, leading to a solubility of approximately 1.9 × 10−5, consistent with the given Ksp value.
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