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Match List – I (Colloid Preparation Method) with List – II (Chemical Reaction) List-I (a) Hydrolysis (b) Reduction (c) Oxidation (d) Double Decomposition List-II (i) 2AuCl3 + 3HCHO + 3H2O → 2Au(sol) + 3HCOOH + 6HCl (ii) As2O3 + 3H2S → As2S3(sol) + 3H2O (iii) SO2 + 2H2S → 3S(sol) + 2H2O (iv) FeCl3 + 3H2O → Fe(OH)3(sol) + 3HCl Choose the most appropriate answer from the options given below.
- (a)-(i), (b)-(ii), (c)-(iii), (d)-(iv)
- (a)-(iv), (b)-(ii), (c)-(iii), (d)-(i)
- (a)-(iv), (b)-(ii), (c)-(i), (d)-(iii)
- (a)-(i), (b)-(ii), (c)-(iv), (d)-(iii)
Correct answer: (a)-(iv), (b)-(ii), (c)-(iii), (d)-(i)
Solution
The correct matches align the colloid preparation methods with their respective chemical reactions: Hydrolysis (a) corresponds to the formation of Fe(OH)3 from FeCl3 and water, Reduction (b) involves the conversion of As2O3 to As2S3 using H2S, Oxidation (c) is represented by the reaction of SO2 with H2S to produce sulfur, and Double Decomposition (d) is exemplified by the reaction of AuCl3 with formaldehyde and water to yield colloidal gold.
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