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For an electrochemical cell Sn(s)|Sn2+(aq, 1M)||Pb2+(aq, 1M)|Pb(s) the ratio [Sn2+]/[Pb2+] when this cell attains equilibrium is ________. (Given: E°Sn2+/Sn = −0.14 V, E°Pb2+/Pb = −0.13 V, 2.303RT/F = 0.06)

1. 2.15
2. 2.15 V
3. 2.15 mol L^-1
4. 2.15 × 10^?

Correct answer: 2.15

Solution

At equilibrium, the Nernst equation indicates that the ratio of the concentrations of the ions is determined by the difference in standard reduction potentials. Given the provided values, the calculated ratio of [Sn2+]/[Pb2+] is 2.15, which reflects the relationship between the two half-reactions.

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