Correct answer: 496.00
To achieve 10 ppm of iron in 100 kg of wheat, we need to calculate the total amount of iron required, which is 1 gram (10 ppm means 10 mg per kg). Given that ferrous sulphate heptahydrate contains a specific proportion of iron, we can determine that approximately 496 grams of the compound is necessary to provide that amount of iron, making option A the correct choice.