Potassium chlorate is prepared by the electrolysis of KCl in basic solution 60H⁻ + Cl⁻ → ClO₃⁻ + 3H₂O + 6e⁻ If only 60% of the reaction, the time (rounded to the nearest hour) required to produce 10 g of KClO₃ using a current of 2 A is ______. (Given : F = 96,500 C mol⁻¹ ; molar mass of KC

Question

Potassium chlorate is prepared by the electrolysis of KCl in basic solution 60H⁻ + Cl⁻ → ClO₃⁻ + 3H₂O + 6e⁻ If only 60% of the reaction, the time (rounded to the nearest hour) required to produce 10 g of KClO₃ using a current of 2 A is ______. (Given : F = 96,500 C mol⁻¹ ; molar mass of KClO₃ = 122 g mol⁻¹)

Accepted Answer

11.00. The calculation involves determining the moles of KClO₃ needed, using Faraday's laws of electrolysis to find the total charge required, and then calculating the time based on the current supplied. Since only 60% of the reaction occurs, the time must account for this efficiency, leading to the final result of approximately 11 hours.

Solution

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