Exams › JEE Main › Chemistry

The final major product of the following reaction is : A benzene ring bearing Me and NH2 substituents (Me and NH2 are meta to each other) is treated with (i) Ac2O/Pyridine (ii) Br2, FeCl3 (iii) OH-/Δ.

1. A benzene ring bearing Me at the upper-left position, Br at the top position, and NH2 at the bottom position.
2. A benzene ring bearing Me at the upper-left position, NH2 at the bottom position, and Br at the lower-right position.
3. A benzene ring bearing Me at the upper-left position, Br at the lower-left position, and NH2 at the bottom position.
4. A benzene ring bearing Me at the upper-left position, Br at the upper-right position, and NH2 at the bottom position.

Correct answer: A benzene ring bearing Me at the upper-left position, Br at the top position, and NH2 at the bottom position.

Solution

The correct option reflects the regioselectivity of electrophilic aromatic substitution reactions, where the amino group directs substitution to the ortho and para positions, while the methyl group is a weakly activating group. In this case, the bromination occurs at the top position, resulting in the final product with the specified substituents in the correct positions.

Related JEE Main Chemistry questions

• Which method is used to purify aniline?
• In Kjeldahl’s method, the nitrogen present in the sample is determined in the form of:
• What product is formed when benzenediazonium chloride (C6H5N2+Cl−) is treated with CuCl?
• When o-methoxybromobenzene is first reacted with sodamide and then treated with ammonia, which compound is obtained as the final product?
• An organic compound A, when treated with NH3, forms B. On heating, B gives C, and C on treatment with Br2 in the presence of KOH yields ethylamine. The compound A is:
• An organic nitrogen-containing compound gives an oily nitrosoamine when treated with aqueous nitrous acid at low temperature. Which compound is it?

⚔️ Practice JEE Main Chemistry free + battle 1v1 →