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Three isomers A, B and C (mol. formula C8H11N) give the following results : A and C — Azotization → P + Q (i) Hydrolysis (ii) Oxidation (KMnO4/H+) → R (product of A) → S (product of C) R has lower boiling point than S B — C6H5SO2Cl → alkali-insoluble product A, B and C, respectively are :

1. o-ethylaniline, N-ethylaniline, p-ethylaniline
2. o-ethylaniline, p-ethyltoluene, m-ethylaniline
3. o-ethylaniline, ethylbenzene, p-ethylaniline
4. o-ethylaniline, p-ethylaniline, m-ethylaniline

Correct answer: o-ethylaniline, p-ethyltoluene, m-ethylaniline

Solution

The correct option identifies the isomers based on their structural differences and reactivity. A is o-ethylaniline, which can undergo azotization and subsequent reactions, while B is p-ethyltoluene, which does not contain a nitrogen atom and thus does not participate in azotization, and C is m-ethylaniline, which fits the criteria of the reactions described.

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