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The major product of the following reaction is : CH3C≡CH (i) Cl2 (1 equiv.) (ii) DI

1. CH3CD(Cl)CHD(I)
2. CH3CD2CH(Cl)(I)
3. CH3CD(Cl)CHD2
4. CH3C(Cl)(I)CHD2

Correct answer: CH3CD(Cl)CHD(I)

Solution

The correct option is formed through the addition of Cl2 and DI to the alkyne, resulting in the substitution of one hydrogen atom with chlorine and another with deuterium, leading to the specific arrangement of substituents on the carbon chain.

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