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Consider the following reversible chemical reactions: A2(g) + B2(g) ⇌ 2AB(g) ...(1) 6AB(g) ⇌ 3A2(g) + 3B2(g) ...(2) The relation between K1 and K2 is:
- K2 = K1^-3
- K1K2 = 1/3
- K1K2 = 3
- K2 = K1^3
Correct answer: K1K2 = 3
Solution
The relationship between the equilibrium constants K1 and K2 can be derived from the stoichiometry of the reactions. Since reaction (2) is the reverse of reaction (1) multiplied by 3, K2 is equal to K1 raised to the power of 3, leading to K1K2 = 3.
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