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Given E°Cr³⁺/Cr = -0.72 V, E°Fe²⁺/Fe = -0.42 V. The potential of the cell Cr|Cr³⁺ (0.1 M)||Fe²⁺ (0.01 M)|Fe is

1. 0.26 V
2. 0.336 V
3. -0.339
4. 0.26 V

Correct answer: -0.339

Solution

The cell potential is calculated using the Nernst equation, which accounts for the standard reduction potentials and the concentrations of the ions involved. In this case, the negative cell potential indicates that the reaction is not spontaneous under the given conditions.

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