An optically active alkyl halide C4H9Br [A] reacts with hot KOH dissolved in ethanol and forms alkene [B] as major product which reacts with bromine to give dibromide [C]. The compound [C] is converted as a gas [D] upon reacting with alcoholic NaNH2. During hydration 1 gram of gas [D] is a

Question

An optically active alkyl halide C4H9Br [A] reacts with hot KOH dissolved in ethanol and forms alkene [B] as major product which reacts with bromine to give dibromide [C]. The compound [C] is converted as a gas [D] upon reacting with alcoholic NaNH2. During hydration 1 gram of gas [D] is added to 1 mole of water on warming with mercuric sulphate and dilute acid at 333 K to form compound [E]. The IUPAC name of compound [E] is:

Accepted Answer

Butan-2-one. The correct option is Butan-2-one because the reaction sequence indicates that the alkene formed is a symmetrical compound that, upon hydration with mercuric sulfate and dilute acid, leads to the formation of a ketone. In this case, the addition of water to the double bond of but-2-yne results in butan-2-one, which is the only ketone among the options provided.

Solution

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