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Identify the correct set of reagents or conditions ‘X’ and ‘Y’ in the following set of transformation.
CH3 – CH2 – CH2 – Br —X→ Product —Y→ CH3 – CH(Br) – CH3
- X = conc.alc. NaOH, 80°C, Y = Br2/CHCl3
- X = dil.aq. NaOH, 20°C, Y = HBr/acetic acid
- X = conc.alc. NaOH, 80°C, Y = HBr/acetic acid
- X = dil.aq. NaOH, 20°C, Y = Br2/CHCl3
Correct answer: X = conc.alc. NaOH, 80°C, Y = HBr/acetic acid
Solution
The correct option involves using concentrated alcoholic NaOH at high temperature to facilitate elimination, forming an alkene intermediate, which is then treated with HBr in acetic acid to achieve the desired bromination at the more substituted carbon, resulting in the final product.
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