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ExamsJEE MainChemistry

The product (C) in the below mentioned reaction is: CH3 – CH2 – CH2 – Br KOH(alc), Δ → B A HBr → B KOH(aq) → C

  1. Propene
  2. Propan-2-ol
  3. Propan-1-ol
  4. Propyne

Correct answer: Propan-2-ol

Solution

The reaction sequence involves the elimination of bromine to form an alkene, followed by hydration, which results in the formation of an alcohol. In this case, the product is propan-2-ol, as the hydration of the alkene leads to the formation of the secondary alcohol.

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