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Which of the following expressions is correct in case of a CsCl unit cell (edge length 'a')?

1. (1) rCs+ + rCl− = a/2
2. (2) rCs+ + rCl− = (√3/2) a
3. (3) rCs+ + rCl− = a/√2
4. (4) rCs+ + rCl− = a

Correct answer: (2) rCs+ + rCl− = (√3/2) a

Solution

In a CsCl unit cell, the cesium ions (Cs+) and chloride ions (Cl−) are located at the corners and the body center of the cubic structure, respectively. The distance between the ions can be derived from the geometry of the cube, leading to the relationship that their combined radii equal (√3/2) times the edge length 'a'.

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