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Match List I and List II. List-I (Polymer) A. {–CH2–C(Cl)=CH–CH2–}n B. {–NH–(CH2)6–NH–CO–(CH2)4–CO–}n C. {–CH2–CH(Cl)–}n D. {–O–H?} List-II (Nature) I. Thermosetting polymer II. Fibers III. Elastomer IV. Thermoplastic polymer

1. A-II, B-III, C-IV, D-I
2. A-III, B-II, C-IV, D-I
3. A-III, B-I, C-IV, D-II
4. A-I, B-III, C-IV, D-II

Correct answer: A-III, B-II, C-IV, D-I

Solution

The correct option matches the structures of the polymers with their respective categories: A is an elastomer due to its flexible structure, B is a fiber because of its strong, linear arrangement, C is a thermoplastic polymer as it can be reshaped upon heating, and D represents a thermosetting polymer due to its cross-linked structure that hardens permanently.

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