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When 200 mL of 0.2 M acetic acid is shaken with 0.6 g of wood charcoal, the final concentration of acetic acid after adsorption is 0.1 M. The mass of acetic acid adsorbed per gram of carbon is ______ g.
- 2.00
- 0.20
- 20.0
- 0.02
Correct answer: 2.00
Solution
Initial moles = 0.2 L x 0.2 M = 0.04 mol; final = 0.2 L x 0.1 M = 0.02 mol, so 0.02 mol adsorbed = 0.02 x 60 = 1.2 g. Per gram of charcoal = 1.2/0.6 = 2.0 g.
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