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Atoms of element X form hcp lattice and those of element Y occupy 2/3 of its tetrahedral voids. The percentage of element X in the lattice is ________. (Nearest integer)
- 43.00
- 43.00
- 43.00
- 43.00
Correct answer: 43.00
Solution
In a hexagonal close-packed (hcp) lattice, there are 6 tetrahedral voids for every 2 atoms of the host element. Since element Y occupies 2/3 of these voids, the calculation shows that element X constitutes approximately 43% of the total mass in the lattice.
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