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ExamsJEE MainChemistry

Match items of List I with those of List II. List-I (Property) (a) Diamagnetism (b) Ferrimagnetism (c) Paramagnetism (d) Antiferromagnetism List-II (Example) (i) MnO (ii) O2 (iii) NaCl (iv) Fe3O4 Choose the most appropriate answer from the options given below:

  1. (a) → (i), (b) → (ii), (c) → (iii), (d) → (iv)
  2. (a) → (i), (b) → (iii), (c) → (iv), (d) → (ii)
  3. (a) → (iii), (b) → (iv), (c) → (ii), (d) → (i)
  4. (a) → (iv), (b) → (ii), (c) → (i), (d) → (iii)

Correct answer: (a) → (iii), (b) → (iv), (c) → (ii), (d) → (i)

Solution

The correct matches align with the properties of the materials: NaCl is diamagnetic due to its lack of unpaired electrons, Fe3O4 exhibits ferrimagnetism because of its unequal magnetic moments, O2 is paramagnetic as it has unpaired electrons, and MnO shows antiferromagnetism due to the antiparallel alignment of its magnetic moments.

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