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In CH2 = C = CH – CH3 molecule, the hybridization of carbon 1, 2, 3 and 4 respectively are:

1. sp3, sp, sp2, sp3
2. sp2, sp, sp2, sp3
3. sp2, sp, sp, sp3
4. sp3, sp3, sp2, sp3

Correct answer: sp2, sp, sp2, sp3

Solution

In CH2=C=CH-CH3, C1 (=CH2) is sp2, C2 (central cumulene carbon with two double bonds) is sp, C3 (=CH-) is sp2, and C4 (CH3) is sp3. So the order is sp2, sp, sp2, sp3.

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