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Excess of isobutane on reaction with Br2 in presence of light at 125°C gives which one of the following, as the major product?

1. CH3-C(Br)(CH3)-CH2-Br
2. CH3-CH(CH2Br)-CH2Br
3. CH3-CH(CH3)-CH2Br
4. CH3-C(Br)(CH3)-CH3

Correct answer: CH3-C(Br)(CH3)-CH3

Solution

The major product is CH3-C(Br)(CH3)-CH3 because the reaction involves free radical bromination, which favors the formation of the most stable tertiary radical. Isobutane has a tertiary carbon that can stabilize the radical formed during the reaction, leading to the preferential formation of this product.

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