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A binary compound, atoms of element A form a ccp structure and those of element M occupy 2/3 of the tetrahedral voids of the hcp structure. The formula of the binary compound is:

1. M2A3
2. M4A3
3. M4A
4. MA3

Correct answer: M4A3

Solution

For N atoms of A in a close-packed lattice there are 2N tetrahedral voids; M fills 2/3 of them = 4N/3. So M:A = 4N/3 : N = 4:3, giving the formula M4A3.

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