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Arrange the following bonds according to their average bond energies in descending order: C–Cl, C–Br, C–F, C–I

1. C–F > C–Cl > C–Br > C–I
2. C–I > C–Br > C–Cl > C–F
3. C–Cl > C–Br > C–I > C–F
4. C–Br > C–I > C–Cl > C–F

Correct answer: C–F > C–Cl > C–Br > C–I

Solution

Carbon-halogen bond energy decreases as the halogen gets larger: C-F > C-Cl > C-Br > C-I.

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