For Freundlich adsorption isotherm, a plot of log (x/m) (y-axis) and log p (x-axis) gives a straight line. The intercept and slope for the line are 0.4771 and 2, respectively. The mass of gas, adsorbed per gram of adsorbent if the initial pressure is 0.04 atm, is ______ × 10⁻⁴ g. (log 3 =

Question

For Freundlich adsorption isotherm, a plot of log (x/m) (y-axis) and log p (x-axis) gives a straight line. The intercept and slope for the line are 0.4771 and 2, respectively. The mass of gas, adsorbed per gram of adsorbent if the initial pressure is 0.04 atm, is ______ × 10⁻⁴ g. (log 3 = 0.4771)

Accepted Answer

48.00. Intercept log k = 0.4771 gives k = 3 and slope 1/n = 2, so x/m = 3*(0.04)^2 = 0.0048 g = 48.00 x 10^-4 g.

Solution

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