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The major product formed in the following reaction is: CH3CH = CHCH(CH3)2 HBr →

1. CH3CH2CH2C(Br)(CH3)2
2. Br(CH2)3CH(CH3)2
3. CH3CH2CH(Br)CH(CH3)2
4. CH3CH(Br)CH2CH(CH3)2

Correct answer: CH3CH2CH2C(Br)(CH3)2

Solution

The correct option is the result of Markovnikov's rule, where HBr adds across the double bond, leading to the more stable carbocation. In this case, the bromine atom attaches to the more substituted carbon, resulting in the formation of the branched product.

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