If a reaction follows the Arrhenius equation, the plot ln k vs 1/(RT) gives straight line with a gradient (-y) unit. The energy required to activate the reactant is:

y unit
yR unit
y/R unit
-y unit

Correct answer: y unit

Solution

The gradient of the plot ln k vs 1/(RT) is equal to -Ea/R, where Ea is the activation energy. Therefore, the activation energy can be expressed as y unit when considering the negative sign in the gradient.

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