Exams › JEE Main › Chemistry

The ratio of number of atoms present in a simple cubic, body centered cubic and face centered cubic structure respectively:

1. 1: 8: 1
2. 4: 2: 1
3. 1: 2: 4
4. 4: 2: 3

Correct answer: 1: 2: 4

Solution

Simple cubic has 8 corners x 1/8 = 1 atom; BCC has 1 (corners) + 1 (body centre) = 2 atoms; FCC has 1 (corners) + 6 x 1/2 (faces) = 4 atoms. The ratio is 1 : 2 : 4.

Related JEE Main Chemistry questions

• Glass is classified as a
• In the wurtzite crystal lattice, what are the coordination numbers of Zn2+ and S2- respectively?
• In KBr, the coordination number of each ion changes from X to Y when the crystal is subjected to which condition?
• How many carbon atoms are present in one unit cell of the diamond crystal structure?
• A sodium chloride crystal has a pycnometric density of 2.165 × 10³ kg m⁻³ and an X-ray density of 2.178 × 10³ kg m⁻³. What fraction of lattice sites are vacant in the crystal?
• Which set of unit-cell parameters represents a cubic lattice, if the edge lengths are a, b, c and the interaxial angles are α, β, and γ?

⚔️ Practice JEE Main Chemistry free + battle 1v1 →