Exams › JEE Main › Chemistry

The reaction of propene with HOCl (Cl2 + H2O) proceeds through the intermediate: (1) CH3–CH2–CH2–OH (2) CH3–CH+–CH2–Cl (3) CH3–CH(OH)–CH2+ (4) CH3–CHCl–CH2+

1. CH3–CH2–CH2–OH
2. CH3–CH+–CH2–Cl
3. CH3–CH(OH)–CH2+
4. CH3–CHCl–CH2+

Correct answer: CH3–CH+–CH2–Cl

Solution

The correct option, CH3–CH+–CH2–Cl, represents a carbocation intermediate formed during the electrophilic addition of HOCl to propene, where the double bond reacts with the electrophile, leading to the formation of a positively charged carbon atom.

Related JEE Main Chemistry questions

• Why is the chlorine atom in vinyl chloride comparatively less reactive?
• What is the product obtained when neopentyl bromide undergoes the Wurtz reaction?
• Which of the following reactions is most likely to produce a hydrocarbon in high yield with ease?
• Which of the following reactions proceeds by an S_N2 mechanism?
• Identify the incorrect statement among the following:
• When chloroform is exposed to air and sunlight by keeping it open, what product is formed?

⚔️ Practice JEE Main Chemistry free + battle 1v1 →