Exams › JEE Main › Chemistry

What is the major product formed when C6H5CH2CH(OH)CH(CH3)2 is treated with concentrated H2SO4?

1. C6H5CH=CHCH(CH3)2
2. C6H5CH2CH=C(CH3)2
3. C6H5CH2CH2C(CH3)=CH2
4. C6H5CH=C(CH3)CH(CH3)2

Correct answer: C6H5CH=CHCH(CH3)2

Solution

The correct option is formed through dehydration of the alcohol group in the presence of concentrated sulfuric acid, leading to the formation of a double bond between the carbon atoms, resulting in an alkene. This reaction favors the formation of the most stable alkene, which in this case is the product with the phenyl group and the double bond adjacent to it.

Related JEE Main Chemistry questions

• Why is ortho-nitrophenol less soluble in water than the meta- and para-nitrophenol isomers?
• Which of the following structures represents vinylcarbinol?
• Which of the following is NOT a starting material used for the preparation of iodoform?
• Iodoform is formed from all of the following except:
• Which reagent can convert CH3CH2OH into CH3CHO?
• Which reagent can be reacted with phenylmagnesium bromide to obtain 2-phenylethanol?

⚔️ Practice JEE Main Chemistry free + battle 1v1 →