Correct answer: n-propyl alcohol
The reaction sequence starts with ethanol (CH3CH2OH) which, when treated with phosphorus and iodine, undergoes a halogenation to form an alkyl iodide. This alkyl iodide then reacts with magnesium to form a Grignard reagent, which upon reaction with formaldehyde (HCHO) produces a primary alcohol. Hydrolysis of this product yields n-propyl alcohol, confirming that D is n-propyl alcohol.